Pupil outcome: I can understand the nature of rotations and appreciate what changes and what is invariant. Key learning points: - The length of the lines do not change when rotated - The angles inside an object do not change when rotated...

Pupil outcome: I can calculate trigonometric ratios for 30° and 60°. Key learning points: - The trigonometric ratios for 30° and 60° can be calculated using an equilateral triangle - The triangle should have lengths of 2 units - By...

Pupil outcome: I can derive and use the formula for the sine rule. Key learning points: - The sides of a triangle are proportional to the sines of their opposite angles - A diagram can aid with understanding this - The sine rule is...

Pupil outcome: I can use my knowledge of percentages to solve problems. Key learning points: - A context can be evaluated to determine what sort of percentage calculation is involved. - As percentages can be written as fractions and...

Pupil outcome: I can use my knowledge of plotting coordinates to solve problems. Key learning points: - You can describe the relationship between coordinate pairs in words. - It is possible to identify points which do or do not follow a...

Pupil outcome: I can use the formula for the area of any triangle. Key learning points: - The formula for the area of any triangle can be used if the lengths of 2 sides are known - The size of the angle between the two sides must also be...

Pupil outcome: I can use the properties of a rhombus to construct a perpendicular bisector of a line segment. Key learning points: - A rhombus can be constructed from two congruent isosceles triangles - The diagonals of a rhombus meet at...

Pupil outcome: I can construct a triangle given the three required side lengths. Key learning points: - The first side can be drawn accurately with a ruler - A pair of compasses should be used to indicate potential positions for the...

Pupil outcome: I can understand the effect of an enlargement on the perimeter of a shape. Key learning points: - An enlargement means the object and image are similar. - All lengths in the object have been multiplied by the scale factor....

Pupil outcome: I can use my knowledge of percentages to solve problems. Key learning points: - A context can be evaluated to determine what sort of percentage calculation is involved. - As percentages can be written as fractions and...

Pupil outcome: I can draw and translate simple shapes on the full coordinate grid Key learning points: - To translate a shape is to move it in a horizontal or vertical direction or a combination of the two. - The translation will give a...

Pupil outcome: I can calculate the perimeter of a 2D shape by adding together the lengths of the sides. Key learning points: - Perimeter is the sum of the side lengths of a 2D shape. - If you measure the side lengths you can add them to...

Pupil outcome: I can calculate the scale factor used to enlarge an area and use it to find missing lengths. Key learning points: - You can calculate the scale factor from the two areas. - Having calculated the scale factor, you can find...

Pupil outcome: I can identify which side length is missing and use the appropriate form of Pythagoras' theorem to calculate it. Key learning points: - The hypotenuse is the side opposite the right angle. - It does not matter which of the...

Pupil outcome: I can construct a triangle given two of the required side lengths and the size of the angle between them. Key learning points: - The first side can be drawn accurately with a ruler - The compass should be used to indicate...

Pupil outcome: I can identify the features of Fibonacci and alternating sequences. Key learning points: - The next term in the Fibonacci sequence is the sum of the previous two terms. - The Fibonacci sequence can be represented...

Pupil outcome: I can use Pythagoras' theorem to find the length of the hypotenuse. Key learning points: - The sum of the squares of the two shorter sides equals the square of the longest side. - The longest side is always opposite the...

Pupil outcome: I can use my knowledge of algebraic manipulation to solve problems. Key learning points: - Quadratic equations can model real-life situations. - Solutions would need to be interpreted in context. - The difference of two...

Pupil outcome: I can solve quadratic equations algebraically by factorising where rearrangement is required. Key learning points: - In order for factorising to be a valid method, the quadratic must equal zero. - To achieve a product of...

In this video, we do two quadratics word problems. The first involves two square and their areas. The second involves a right triangle with polynomial side lengths.

In this video, we investigate how changing the linear dimensions of a three dimensional solid affects the volume and surface area. Specifically, how do we solve for missing values (like side length, volume and surface area) when we are...

In this video, we investigate how changing the linear dimensions of a 3d solid will affect the volume and surface area. After a dilation of a certain scale factor, how can that scale factor be used to predict the new volume or surface...

In this video, we practice calculating how volume and surface area would change as we change the linear dimensions of 3d figures.

How to use the Law of Sines to find sides and angles. In this video, we will see how to use the Law of Sines in two practice problems. We will first solve for a side length in a triangle, then we will solve for an angle.