Instructional Video18:05
Khan Academy

Proof: lim (sin x)/x

11th - Higher Ed
By looking at the expression (sin x)/x that is not defined at the limit value of 0, Sal uses the squeeze theorem to show that the function can be bound between two other functions that are defined at the limit value, so the limit can...
Instructional Video3:57
Curated OER

Squeeze Theorem

6th - 9th
The Squeeze Theorem helps describe a series of limits. Take four minutes to view this well explained and clear video covering a complex topic. Teacher facilitation may be necessary.
Instructional Video
Khan Academy

Khan Academy: Pre Calculus: Proof: Lim (Sin X)/x

9th - 10th
Video utilizing the Squeeze Theorem to prove that the limit as x approaches 0 of (sin x)/x is equal to 1. Incorporates trigonometry and the unit circle. Illustrates the result graphically on a virtual graphing calculator. This video is...
Instructional Video
Dartmouth College

Dartmouth College: Mqed: That's Calculus!: Episode 2 and 3: The Formal Limit

9th - 10th
Students learn about the epsilon-delta definition of limit. Josh plays the epsilon-delta game and visits the For All There Exists Cafe as he explains the formal definition of limit in these video lessons.
Instructional Video
Khan Academy

Khan Academy: Pre Calculus: Squeeze Theorem

9th - 10th
Instructional video explaining the Squeeze Theorem. The theorem is first described using a real-life situation, then the theorem is illustrated graphically using three arbitrary functions. Does not include a proof of the theorem. This...
Instructional Video
Khan Academy

Khan Academy: Squeeze Theorem: Squeeze Theorem

9th - 10th
This video is an intuition (but not a proof) of the Squeeze Theorem.
Instructional Video
Khan Academy

Khan Academy: Squeeze Theorem: Proof: Lim (Sin X)/x

9th - 10th
Using the squeeze theorem to prove that the limit as x approaches 0 of (sin x)/x =1