Instructional Video4:19
Brian McLogan

Sketch a triangle given a trig angle then determine remaining trig functions of angle

12th - Higher Ed
πŸ‘‰ Learn how to evaluate the six trigonometric functions given the value of one of the trigonometric functions. When given the value of one of the trigonometric functions of an angle, we can evaluate the values of the other trigonometric...
Instructional Video4:55
Brian McLogan

Evaluate for sine cosine and tangent using reference angles

12th - Higher Ed
πŸ‘‰ Learn how to evaluate trigonometric functions of a given angle. Given an angle greater than 2pi in radians, to evaluate the trigonometric functions of the given angle, we first determine the smallest positive coterminal angle of the...
Instructional Video3:47
Brian McLogan

Pre-Calculus - Find All of the Solutions of an Equation Using the Double Angle Formulas

12th - Higher Ed
πŸ‘‰ Learn how to use the double angle identities to solve trigonometric equations. When we have equations with a double angle we will apply the identities to create an equation that can help solve by inverse operations or factoring. We...
Instructional Video6:13
Brian McLogan

Learn how to find the angle between two vectors

12th - Higher Ed
Learn how to determine the angle between two vectors. To determine the angle between two vectors you will need to know how to find the magnitude, dot product and inverse cosine. Then, the angle between two vectors is given by the inverse...
Instructional Video4:55
Brian McLogan

Learn how to write the vector in component form given magnitude and direction

12th - Higher Ed
Learn how to write a vector in component form when given the magnitude and direction. When given the magnitude (r) and the direction (theta) of a vector, the component form of the vector is given by r(cos(theta), sin(theta)).
Instructional Video2:07
Brian McLogan

How to find the component form of a vector given the magnitude and direction

12th - Higher Ed
Learn how to write a vector in component form when given the magnitude and direction. When given the magnitude (r) and the direction (theta) of a vector, the component form of the vector is given by r(cos(theta), sin(theta)).
Instructional Video1:28
Brian McLogan

Learn to evaluate the limit of tangent

12th - Higher Ed
πŸ‘‰ Learn how to evaluate the limit of a function involving trigonometric expressions. The limit of a function as the input variable of the function tends to a number/value is the number/value which the function approaches at that time....
Instructional Video2:38
Brian McLogan

Sketch a triangle given a trig angle then determine remaining trig functions of angle

12th - Higher Ed
πŸ‘‰ Learn how to evaluate the six trigonometric functions given the value of one of the trigonometric functions. When given the value of one of the trigonometric functions of an angle, we can evaluate the values of the other trigonometric...
Instructional Video4:29
Brian McLogan

Given a lengths of a right triangle evalute the six trig properties

12th - Higher Ed
πŸ‘‰ Learn how to evaluate the six trigonometric functions given a right triangle. A right triangle is a triangle with 90 degrees as one of its angles. A right triangle is made up of two legs, which formed the sides of the 90 degrees angle...
Instructional Video1:30
Brian McLogan

Evaluating Inverse Trigonometric Functions

12th - Higher Ed
πŸ‘‰ Learn how to evaluate the inverse of reciprocal trigonometric functions. Recall that the reciprocal trigonometric functions are given by the ratio of 1 and the corresponding trigonometric function. When an angle is unknown but the...
Instructional Video2:11
Brian McLogan

Evaluate the six trig functions when given an angle in radians

12th - Higher Ed
πŸ‘‰ Learn how to evaluate the six trigonometric functions of a given angle. When given an angle we locate the angle on the unit circle. Then using the coordinate of the terminal side of the angle on the unit circle and the definitions of...
Instructional Video4:50
Brian McLogan

Solve trigonometric equation using identities and zero product property

12th - Higher Ed
πŸ‘‰ Learn how to solve trigonometric equations using the zero product property. The zero product property states that when the product of two quantities is equal to 0, then either of the quantities is zero. When solving factored...
Instructional Video3:05
Brian McLogan

How does an oblique triangle compare to a right triangle

12th - Higher Ed
πŸ‘‰ Learn how to solve for the length of the sides and the measures of the angles of a triangle using the law of sines. The law of sines is used in determining the length of the opposite side to a known angle measure or the measure of the...
Instructional Video8:10
Brian McLogan

How do you understand the direction of an angle

12th - Higher Ed
Learn how to determine the magnitude and direction of a vector. The magnitude of a vector is the length of the vector. The magnitude of a vector is obtained by taking the square root of the sum of the squares of the components of the...
Instructional Video2:43
Brian McLogan

Learn how to find the angle of a vector not in component form

12th - Higher Ed
Learn how to determine the magnitude and direction of a vector. The magnitude of a vector is the length of the vector. The magnitude of a vector is obtained by taking the square root of the sum of the squares of the components of the...
Instructional Video2:14
Brian McLogan

How to graph a polar point and then convert to rectangular form

12th - Higher Ed
How to graph a polar point and then convert to rectangular form
Instructional Video5:59
Brian McLogan

How To Write a Proof - Proving Parallel Lines

12th - Higher Ed
πŸ‘‰ Learn how to write a proof when given angles from parallel lines and a transversalWe will explore angle relationships with parallel lines and a transversal. Parallel lines are two lines on a plane that will never intersect and a...
Instructional Video4:14
Brian McLogan

Determine the missing angles using complementary and triangle angle sum

12th - Higher Ed
πŸ‘‰ Learn how to find the missing side of a triangle. A triangle is a polygon with three sides. Triangles are classified on the basis of the angles or on the basis of the sides. The classification of a triangle on the basis of the sides...
Instructional Video12:47
Curated Video

Create a computer vision system using decision tree algorithms to solve a real-world problem : Histogram of Oriented Gradients (HOG)

Higher Ed
From the section: Computer Vision Basics: Part 3. In this section, we’ll cover the advanced features of Computer Vision. Computer Vision Basics: Part 3: Histogram of Oriented Gradients (HOG)
Instructional Video9:21
Flipping Physics

Physics "Magic Trick" on an Incline

12th - Higher Ed
Understand the forces acting on an object on an incline by analyzing the forces on a β€œfloating block”.
Instructional Video10:49
Brian McLogan

Master Solving for the missing sides of a triangle for ASA and AAS using law of sines

12th - Higher Ed
Master Solving for the missing sides of a triangle for ASA and AAS using law of sines
Instructional Video4:42
Brian McLogan

Find the missing length of a triangle using the sine function

12th - Higher Ed
In this video I show you how to find the missing length of a triangle using the sine function. We are given a right triangle and two side lengths and a missing length. We show a right triangle and label the hypotenuse, and two legs the...
Instructional Video3:26
Curated Video

GCSE Secondary Maths Age 13-17 - Geometry & Measures: Geometry - Explained

9th - 12th
SchoolOnline's Secondary Maths videos are brilliant, bite-size tutorial videos delivered by examiners. Ideal for ages 13-17, they cover every key topic and sub topic covered in GCSE Maths in clear and easy to follow steps. This video...
Instructional Video5:47
Curated Video

GCSE Secondary Maths Age 13-17 - Geometry & Measures: Circle Theorems - Explained

9th - 12th
SchoolOnline's Secondary Maths videos are brilliant, bite-size tutorial videos delivered by examiners. Ideal for ages 13-17, they cover every key topic and sub topic covered in GCSE Maths in clear and easy to follow steps. This video...