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4 comments so far

  1. Thank you for your comments. This article has been fixed.

  2. I agree with Judy. Interesting discussion though.

  3. P(1) * P(1) = 1/6 * 1/6 = 1/36
    - this is correct but what about getting only one "1". This only considers the probability of getting two "1s" in a row. You have to add another possible outcomes
    P(1) * P(not 1) = 1/6 * 5/6 = 5/36
    Therfore,
    P(at least one "1") = 5/36 + 1/36 = 6/36 = 1/6
    and so there is no mistake above!

  4. Ms. Callaghan's comment is true if you are considering an "or" situation, meaning that a one could show up on die A or die B. If you are considering an "and", meaning that a one shows up on both die A and die B, the probability would be 1/36. P(1) * P(1) = 1/6 * 1/6 = 1/36 or 2.7%. Either way, 2/12 would not be the probability of the event.

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